Flocon de von Koch, fractales et carte n°3

On parle de fractales et on génère la troisième carte de la collection Ulule ! Le code final (encore optimisable !) import math from PIL import Image, ImageDraw width = 1748 height = 1240 vonkoch = Image.new('RGB', (width,height), (255,255,255)) draw = ImageDraw.Draw(vonkoch) def koch(A,B,n): if (n==0): draw.line((A,B), fill=(0,0,0), width=1) else: M2 = sim(A,B,math.pi/6,1/math.sqrt(3)) koch(M2,A,n-1) koch(B,M2,n-1) def sim(A,B,alpha,mu): C = [B[0]-A[0],B[1]-A[1]] D = [mu*(C[0]*math.cos(alpha)+C[1]*math.sin(alpha)),mu*(-C[0]*math.sin(alpha)+C[1]*math.cos(alpha))] return [A[0]+D[0],A[1]+D[1]] def flocon(A,B): C = sim(B,A,math.pi/3,1) koch(A,B,14) koch(B,C,14) koch(C,A,14) L = 600 for i in range(3): for j in range(3): A0 = [1748/2+L/2+L*(i-1),height/2+L*math.sqrt(3)/6+L*2/3*math.sqrt(3)*(j-1)+L/3*math.sqrt(3)*(i-1)] B0 = [1748/2-L/2+L*(i-1),height/2+L*math.sqrt(3)/6+L*2/3*math.sqrt(3)*(j-1)+L/3*math.sqrt(3)*(i-1)] flocon(A0,B0) vonkoch.show()